The BOOM

In many cases, the number of elements which will comprise the antenna will be a function length of boom which one will be able or wish to lay out. The section of aluminium being very often sold out of tube of 6 m, the coasts given on this page will thus be calculated for a boom of 6 m.
Small recall: the wavelength L (in m) = 300/the frequency (in MHz) is for a frequency of 27.600 MHz, = > L = 300/27.600 = 10.869 m
the conventional spacings between elements being of 0.25, 0.2, 0.17, 0.15, 0.13, or 0.1 X the wavelength L One will thus have possible spacings according to: 0.25 L = 2.717 m, 0.2 L = 2.174 m, 0.17 L = 1.848 m, 0.15 L = 1.630 m, 0.13 L = 1.413 m and 0.1 L = 1.087 m
On a boom of 6m, one can thus have is:

Thus, according to the length of boom which one lays out, one can "juggle" between the various spacings (but always into decreasing of the reflectors towards the directors) according to the performances which one wishes to privilege.
If one wishes supports a good report/ratio before/back with the detriment of the profit, one will choose a number of more restricted element but with more significant spacings.
Conversely, if it is the profit which is required then with length of equal boom, an element moreover is more interesting than larger spacings.
If you have enough place to then use more than 6 m of boom you do not deprive, the performances will be only better.
To assemble two tubes, I advise you not "to bore" the two parts but rather to take them in "sandwich" with two aluminium plates as represented on the sight opposite.